The titration of 25.0 mL of an unknown concentration H₂SO₄ solution requires 83.6 mL of 0.12 M LiOH solution.What is the concentration of the H₂SO₄ solution (in M)? A) 0.20 M B) 0.40 M C) 0.10 M D) 0.36 M E) 0.25 M

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Quizplus · Accepted Answer

The concentration of the unknown solution can be found using the titration formula: $M_1V_1 = M_2V_2$, where $M_1$ and $M_2$ are the molarities of the two solutions, and $V_1$ and $V_2$ are their volumes. Given $M_2 = 0.12 \, M$, $V_2 = 83.6 \, mL$, and $V_1 = 25.0 \, mL$, we can solve for $M_1$: $M_1 = \frac{M_2V_2}{V_1} = \frac{0.12 \, M \times 83.6 \, mL}{25.0 \, mL} = 0.40128 \, M$, which rounds to $0.40 \, M$, making choice B correct.

The Titration of 25