Determine the number of grams H₂ formed when 250.0 mL of 0.743 M HCl solution reacts with 3.41 × 10²³ atoms of Fe according to the following reaction. 2 HCl(aq)+ Fe(s)→ H₂(g)+ FeCl₂(aq) A) 0.374 g B) 1.33 g C) 1.14 g D) 0.187 g E) 1.51 g

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First, calculate moles of HCl: 0.250 L * 0.743 mol/L = 0.18575 mol. The reaction requires 2 moles of HCl per mole of H2, so moles of H2 = 0.18575 / 2 = 0.092875 mol. Next, calculate moles of Fe: 3.41 × 10^23 atoms / 6.022 × 10^23 atoms/mol = 0.566 mol. Fe is in excess, so HCl limits the reaction. Finally, convert moles of H2 to grams: 0.092875 mol * 2.016 g/mol = 0.187 g.

Determine the Number of Grams H2 Formed When 250

Determine the Number of Grams H₂ Formed When 250