According to the following reaction,how many moles of Fe(OH)₂ can form from 175.0 mL of 0.227 M LiOH solution? Assume that there is excess FeCl₂. FeCl₂(aq)+ 2 LiOH(aq)→ Fe(OH)₂(s)+ 2 LiCl(aq) A) 3.97 × 10^-2 moles B) 2.52 × 10^-2 moles C) 1.99 × 10^-2 moles D) 5.03 × 10^-² moles E) 6.49 × 10^-2 moles

Question

Quizplus · Accepted Answer

First, we need to use the given concentration and volume to calculate the moles of LiOH:

0.227 mol/L x 0.175 L = 0.0397 mol LiOH

From the balanced chemical equation, we can see that the mole ratio between FeCl2 and Fe(OH)2 is 1:1. This means that the number of moles of Fe(OH)2 that can form will also be 0.0397 mol.

Therefore, the answer is C, 1.99 × 10^-2 moles.

According to the Following Reaction,how Many Moles of Fe(OH)2 Can

According to the Following Reaction,how Many Moles of Fe(OH)₂ Can