Use the data given below to construct a Born-Haber cycle to determine the lattice energy of CaO. DH°(kJ)
Ca(s) → Ca(g) 193
Ca(g) → Ca⁺(g) + e⁻ 590
Ca⁺(g) → Ca2⁺(g) + e⁻ 1010
2 O(g) → O2(g) -498
O(g) + e⁻ → O⁻(g) -141
O⁻(g) + e⁻ → O2⁻(g) 878
Ca(s) + O2(g) → CaO(s) -635
A) -3414 kJ
B) +1397 kJ
C) -2667 kJ
D) +3028 kJ
E) -2144 kJ
Correct Answer:
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