What is the wavelength of an electron (m = 9.11 × 10^-28 g)moving at 1/5 the speed of light? A) 9.36 × 10^-9 m B) 1.21 × 10^-11 m C) 6.73 × 10^-8 m D) 2.42 × 10^-12 m E) 4.85 × 10^-10 m

Question

Quizplus · Accepted Answer

The de Broglie wavelength is given by λ = h/p, where h is Planck's constant and p is the momentum of the electron. The momentum of the electron is given by p = mv, where m is the mass of the electron and v is its velocity. Substituting these expressions into the de Broglie wavelength equation, we get λ = h/mv. Plugging in the given values, we get λ = (6.626 × 10^-34 J s)/(9.11 × 10^-28 g * (1/5) * (3 × 10^8 m/s)) = 1.21 × 10^-11 m.

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