Calculate the solubility (in g L^-1)of calcium fluoride in water at 25 °C if the K_sp for CaF₂ is 1.5 × 10^-10. A)9.6 × 10^-4 g L^-1 B)2.6 × 10^-2 g L^-1 C)3.3 × 10^-2 g L^-1 D)4.1 × 10^-2 g L^-1

Question

Quizplus · Accepted Answer

The solubility product expression for CaF2 is Ksp = [Ca2+][F-]^2. Let the solubility of CaF2 be s mol/L. Then [Ca2+] = s and [F-] = 2s. Ksp = s(2s)^2 = 4s^3. Solving 4s^3 = 1.5 × 10^-10 gives s = 3.42 × 10^-4 mol/L. The molar mass of CaF2 is 78.07 g/mol, so solubility in g/L is 3.42 × 10^-4 mol/L × 78.07 g/mol = 2.67 × 10^-2 g/L, which is approximately 2.6 × 10^-2 g/L.

Calculate the Solubility (In G L-1)of Calcium Fluoride in Water

Calculate the Solubility (In G L^-1)of Calcium Fluoride in Water