A solution contains 0.021 mol L^-1 Cl⁻ and 0.017 mol L^-1 I⁻. A solution containing copper(I) ions is added to selectively precipitate one of the ions. At what concentration of copper(I) ion will a precipitate begin to form? What is the identity of the precipitate? K_sp(CuCl) = 1.0 × 10^-6, K_sp(CuI) = 5.1 × 10^-12. A) 3.0 × 10^-10mol L^-1, CuI B) 3.0 × 10^-10 mol L^-1, CuCl C) 4.8 × 10^-5 mol L^-1, CuCl D) 4.8 × 10^-5 mol L^-1, CuI E) 3.0 × 10^-5 mol L^-1, both CuCl and CuI are in the precipitate

Question

Quizplus · Accepted Answer

CuI will precipitate first because it has a lower Ksp value. The concentration of Cu⁺ needed to start precipitating CuI is calculated using Ksp = [Cu⁺][I⁻], which gives 3.0 × 10⁻¹⁰ mol L⁻¹.

A Solution Contains 0