What is the pH of a 0.40 mol L^-1 H₂Se solution that has the stepwise dissociation constants K_a1 = 1.3 × 10^-4 and K_a2 = 1.0 × 10^-11? A)2.14 B)3.89 C)4.28 D)5.57

Question

Quizplus · Accepted Answer

The pH is primarily determined by the first dissociation constant (Ka1) because it is much larger than Ka2. Using the formula for pH = -log[H+], where [H+] is approximately equal to the square root of (Ka1 * concentration of H2Se), we find pH ≈ 2.14.

What Is the PH of a 0