Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of LiCl in 13.7 moles of H₂O. A) 0.454 mol kg^-1 B) 0.220 mol kg^-1 C) 0.818 mol kg^-1 D) 0.122 mol kg^-1 E) 0.153 mol kg^-1

Question

Quizplus · Accepted Answer

Molality is calculated as moles of solute per kilogram of solvent. Here, 0.112 moles of LiCl is dissolved in 13.7 moles of H2O. The molar mass of H2O is approximately 18.015 g/mol, so 13.7 moles of H2O is about 0.247 kg. Molality = 0.112 moles / 0.247 kg = 0.454 mol kg^-1.

Determine the Molality of an Aqueous Solution Prepared by Dissolving