If 102.7 g of tin is mixed with 10.9 g of copper to create the alloy pewter, how many moles of metal are present in the pewter?
A) 0.9643 mol total
B) 1.037 mol total
C) 0.6233 mol total
D) 1.604 mol total
E) 0.8675 mol total

Question

Quizplus · Accepted Answer

To calculate the number of moles of each element, we need to divide the mass of each element by its molar mass. The molar mass of tin is 118.71 g/mol and the molar mass of copper is 63.55 g/mol.

For tin:

moles of tin = 102.7 g / 118.71 g/mol = 0.865 mol

For copper:

moles of copper = 10.9 g / 63.55 g/mol = 0.172 mol

So the total number of moles of metal in the pewter is:

0.865 + 0.172 = 1.037 mol

Therefore, the answer is B.

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