Two converging lenses,each with a focal length of 0.080 m,are used in combination to form an image of an object that is located 0.24 m to the left of the left lens in the pair.The distance between the lenses is 0.16 m.
-What is the total magnification of this lens combination?
A)+1/2
B)-1/2
C)+1
D)-1
E)+2

Question

Quizplus · Accepted Answer

The total magnification of the lens combination can be calculated using the formula:
M= -(d_o)/(f_eff)
where d_o is the object distance and f_eff is the effective focal length of the combination of lenses.
To find f_eff, we can use the formula:
1/f_eff = 1/f_1 + 1/f_2 - d/f_1f_2
where f_1 and f_2 are the individual focal lengths of the lenses, and d is the distance between them.
Substituting the given values, we get:
1/f_eff = 1/0.080 + 1/0.080 - 0.16/(0.080 x 0.080)
1/f_eff = 25
f_eff = 0.040 m
Substituting f_eff and d_o into the magnification formula, we get:
M = -(0.24)/(0.040) = -6
Therefore, the total magnification of the lens combination is -6, which corresponds to answer choice D.

Two Converging Lenses,each with a Focal Length of 0