A dime is placed in front of a concave mirror that has a radius of curvature R = 0.30 m.The image of the dime is inverted and three times the size of the dime.Determine the distance between the dime and the mirror.
A)0.20 m
B)0.15 m
C)0.10 m
D)0.60 m
E)0.45 m

Question

Quizplus · Accepted Answer

Given that the image is inverted and three times the size of the object, the magnification (m) is -3. Using the mirror equation and magnification formula, 1/f = 1/v + 1/u and m = -v/u, where f is the focal length, v is the image distance, and u is the object distance. The focal length f = R/2 = 0.15 m. Substituting values and solving, we find u = 0.20 m.

A Dime Is Placed in Front of a Concave Mirror