Determine the energy stored in a 7.09 × 10^-⁷ H inductor that carries a 1.50-A current. A)2.11 × 10^-⁸ J B)3.78 × 10^-⁸ J C)1.09 × 10^-⁷ J D)7.98 × 10^-⁷ J E)6.60 × 10^-⁶ J

Question

Quizplus · Accepted Answer

The energy stored in an inductor is given by the formula $E = \frac{1}{2}LI^2$, where $E$ is the energy in joules, $L$ is the inductance in henrys, and $I$ is the current in amperes. Substituting the given values, $E = \frac{1}{2} \times 7.09 \times 10^7 \times (1.50)^2 = 7.98 \times 10^7$ joules.

Determine the Energy Stored in a 7