The figure shows a simple RC circuit consisting of a 10.0-µF capacitor in series with a resistor.Initially,the switch is open as suggested in the figure.The capacitor has been charged so that the potential difference between its plates is 100.0 V.At t = 0 s,the switch is closed.The capacitor discharges exponentially so that 2.0 s after the switch is closed,the potential difference between the capacitor plates is 37 V.In other words,in 2.0 s the potential difference between the capacitor plates is reduced to 37 % of its original value.
-Calculate the electric potential energy stored in the capacitor before the switch is closed.
A) 0.01 J
B) 0.02 J
C) 0.03 J
D) 0.04 J
E) 0.05 J
Correct Answer:
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