A string with a length of 3.0 m has two adjacent resonances at frequencies 112 Hz and 140 Hz.
-How many antinodes will be found on the 112 Hz resonance?
A)1
B)2
C)3
D)4
E)5

Question

Quizplus · Accepted Answer

The difference between the two adjacent resonant frequencies (140 Hz - 112 Hz = 28 Hz) is the fundamental frequency. The 112 Hz resonance is the 4th harmonic (112 Hz / 28 Hz = 4), which means there are 4 antinodes.

A String with a Length of 3