Given the following logarithms, what would be the pH of this patient
Log of 10 = 1.0
Log of 20 = 1.3
Log of 40 = 1.6
PK = 6.1
A)pH = 7.7
B)pH = 7.4
C)pH = 7.1
D)pH = 6.9

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The Answer of Given the following logarithms, what would be the pH of this patient
Log of 10 = 1.0
Log of 20 = 1.3
Log of 40 = 1.6
PK = 6.1
A)pH = 7.7
B)pH = 7.4
C)pH = 7.1
D)pH = 6.9

Given the Following Logarithms, What Would Be the PH of This