Exhibit 7-7: A group of curriculum designers has developed a new system for teaching phonics to young children.They randomly selected 24 kindergarten students to receive either the old phonics method or the new phonics method.The designers realized that kindergartens have morning and afternoon classes, so they wanted to build this factor into the research design.The following is the mean, standard deviation, and number for each group.
$ \begin{array}{lll}\text { Morning } & {\text { Old }}{} & {\text { New }}{} \ & 16.33 & 13.50 \ &1.03 & 2.74 \& 6 & 6 \ \text { Afternoon } & 13.17 & 16.83 \ & 3.55 & 2.14 \ & 6 & 6\end{array} $
The following is an incomplete summary table of the analysis of variance:
$\begin{array}{ll}
\underline { \text { Source }} & \underline { \text { SS }} & \underline { \text { df }} & \underline { \text { MS}} & \underline { \text { F}}\
\text { Time of Day } & 0.042 \
\text { Lesson Design } & 1.042 \
\text { Interaction }\
\text { Error } & 128.500 \
\text { Total } & 102950
\end{array}$
-Refer to Exhibit 7-7.What is the F value for the Interaction?
A) .006
B) .162
C) 9.864
D) None of these are true.

Question

Exhibit 7-7: A group of curriculum designers has developed a new system for teaching phonics to young children.They randomly selected 24 kindergarten students to receive either the old phonics method or the new phonics method.The designers realized that kindergartens have morning and afternoon classes, so they wanted to build this factor into the research design.The following is the mean, standard deviation, and number for each group.
$ \begin{array}{lll}\text { Morning } & {\text { Old }}{} & {\text { New }}{} \ & 16.33 & 13.50 \ &1.03 & 2.74 \& 6 & 6 \ \text { Afternoon } & 13.17 & 16.83 \ & 3.55 & 2.14 \ & 6 & 6\end{array} $
The following is an incomplete summary table of the analysis of variance:
 $\begin{array}{ll}
\underline { \text { Source }} & \underline { \text { SS }} & \underline { \text { df }} & \underline { \text {  MS}} & \underline { \text {   F}}\
\text { Time of Day } & 0.042 \
\text { Lesson Design } & 1.042 \
\text { Interaction }\
\text { Error } & 128.500 \
\text { Total } & 102950
\end{array}$
-Refer to Exhibit 7-7.What is the F value for the Interaction?
A) .006
B) .162
C) 9.864
D) None of these are true.

Quizplus · Accepted Answer

To find the F value for the interaction, we need to calculate the interaction sum of squares (SS) and degrees of freedom (df). SS_interaction = SS_total - SS_time of day - SS_lesson design - SS_error = 102.500 - 0.042 - 1.042 - 128.500 = -27.084. However, the sum of squares cannot be negative, so we can conclude that there is no interaction effect. Therefore, the F value for the interaction is 0, and the answer is D (None of these are true).

Exhibit 7-7: a Group of Curriculum Designers Has Developed a New