A 100 W light bulb with an amperage of 0.91 A is operating at a potential difference of
A)110 volts.
B)100 volts.
C)11 kilovolts.
D)110 ohms.

Question

Quizplus · Accepted Answer

We can use the formula P = VI, where P is power in watts, V is potential difference in volts, and I is current in amperes.

Substituting the given values, we get:

100 = V x 0.91

Solving for V, we get:

V = 100/0.91 = 109.89

Rounding off to the nearest whole number, we get:

V = 110

Therefore, the potential difference is 110 volts, which corresponds to choice A.

A 100 W Light Bulb with an Amperage of 0