When four hydrogen nuclei fuse to make helium, a small amount of matter is lost. What is the mass difference and energy generated The mass of hydrogen and helium nuclei are$9 1.67 × 10^{-27}$ kg and $6.646 × 10^{-27}$ kg, respectively.
A)$0.034 × 10^{-27}$ kg, $3 × 10^{-12}$ J
B)$0.022 × 10^{-27}$ kg, $2 × 10^{-12 }$J
C)$0.068 × 10^{-27}$ kg, $6 × 10^{-12}$ J
D)$0.011 × 10^{-27}$ kg, $1 × 10^{-12} $J

Question

Quizplus · Accepted Answer

Mass difference = (4 × 1.67 × 10^-27 kg) - (6.646 × 10^-27 kg) = 0.034 × 10^-27 kgEnergy generated = (0.034 × 10^-27 kg) × (3 × 10^8 m/s)^2 = 3 × 10^-12 J

When Four Hydrogen Nuclei Fuse to Make Helium, a Small 91.67×10−279 1.67 × 10^{-27}91.67×10−27

When Four Hydrogen Nuclei Fuse to Make Helium, a Small $9 1.67 × 10^{-27}$