What will the following code display?
String input = "99#7";
Int number;
Try
{
Number = Integer.parseInt(input);
}
Catch(NumberFormatException ex)
{
Number = 0;
}
Catch(RuntimeException ex)
{
Number = 1;
}
Catch(Exception ex)
{
Number = -1;
}
System.out.println(number);
A) 99
B) 997
C) 0
D) 1

Question

Quizplus · Accepted Answer

The code attempts to convert the String "99#7" to an integer using Integer.parseInt(). However, since "99#7" is not a valid integer, a NumberFormatException will be thrown. Thus, the exception will be caught in the first catch block and the value of number will be set to 0. Therefore, the code will display 0.

What Will the Following Code Display