Look at the following pseudocode algorithm: Algorithm gcd(x, y)
If (x < y)
Gcd (y, x)
Else
If (y = 0)
Return x
Else
Return gcd(y, x mod y)
End gcd
What is the base case for the algorithm gcd?
A) x < y
B) y == 0
C) x == 0
D) y > x
Correct Answer:
Verified
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