Which statement is true about the release factors in the termination of translation in E.coli?
A)The release factors methylate the termination codon which blocks the codon from being recognized by a tRNA.
B)The release factors induce conformational changes at the A and P sites of the ribosome that cause the termination of translation.
C)After recognizing the termination codon,the release factors cause the hydrolysis of the peptidyl-tRNA.
D)The release factors are modulators that bind to the ribosomal subunits and cause them to dissociate from each other.

Question

Quizplus · Accepted Answer

The release factors recognize the stop codon and stimulate the hydrolysis of the bond between the peptidyl-tRNA and the last amino acid of the polypeptide chain, causing the release of the protein from the ribosome. Choice A is incorrect because there is no methylation involved in the release factor activity. Choice B is incorrect because conformational changes within the ribosome are required for both the elongation and termination phases of translation, whereas release factors do not induce changes in the ribosome structure but bind to specific sites on the ribosome. Choice D is incorrect because release factors do not bind to the subunits of the ribosome, but to specific sites on the ribosome that are involved in peptide bond hydrolysis.

Which Statement Is True About the Release Factors in the Termination