The expression *s-p; indicates that s is a structure pointer and p, which is also a pointer, is a member of the structure pointed to by s.

Question

The expression *s->p; indicates that s is a structure pointer and p, which is also a pointer, is a member of the structure pointed to by s.

Quizplus · Accepted Answer

The expression *s->p is equivalent to *(s->p), which means "dereference the pointer to the structure pointed to by s and access the member variable p within that structure." Therefore, s is a structure pointer and p is a member of the structure pointed to by s.

The Expression *S->P; Indicates That S Is a Structure Pointer