Evaluate the definite integral.
-$\int_{1}^{3} \frac{8 x+11}{x} d x$
A) $16+11 \ln 3$
B) $8+11 \ln 3$
C) $13+11 \ln 3$
D) $11 \ln 3-3$

Question

Quizplus · Accepted Answer

The integral can be split into two parts: $\int_{1}^{3} 8 \, dx + \int_{1}^{3} \frac{11}{x} \, dx$. The first part evaluates to $8(x)$ from 1 to 3, which is $8(3) - 8(1) = 16$. The second part is $11 \ln|x|$ from 1 to 3, which is $11 \ln 3 - 11 \ln 1 = 11 \ln 3$. Adding these results gives $16 + 11 \ln 3$.

Evaluate the Definite Integral ∫138x+11xdx\int_{1}^{3} \frac{8 x+11}{x} d x∫13​x8x+11​dx A) 16+11ln⁡316+11 \ln 316+11ln3

Evaluate the Definite Integral $\int_{1}^{3} \frac{8 x+11}{x} d x$ A) $16+11 \ln 3$