Find the integral.
-$\int \frac{1}{8-x} d x$
A) $-\ln |8-x|+C$
B) $\ln (8-x)+C$
C) $\ln |8-x|+C$
D) $-\frac{1}{8} \ln |8-x|+C$

Name: Find the integral. -$\int \frac{1}{8-x} d x$ A) $-\ln |8-x|+C$ B) $\ln (8-x)+C$ C) $\ln |8-x|+C$ D) $-\frac{1}{8} \ln |8-x|+C$
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The Answer of Find the integral.
-$\int \frac{1}{8-x} d x$
A) $-\ln |8-x|+C$
B) $\ln (8-x)+C$
C) $\ln |8-x|+C$
D) $-\frac{1}{8} \ln |8-x|+C$

Find the Integral ∫18−xdx\int \frac{1}{8-x} d x∫8−x1​dx A) −ln⁡∣8−x∣+C-\ln |8-x|+C−ln∣8−x∣+C B) ln⁡(8−x)+C\ln (8-x)+Cln(8−x)+C

Find the Integral $\int \frac{1}{8-x} d x$ A) $-\ln |8-x|+C$ B) $\ln (8-x)+C$