Solve the problem.
-The slope to the tangent line of a curve is given by $f^{\prime}(x)=x^{2}-11 x+7$. If the point $(0,5)$ is on the curve, find an equation of the curve.
A)f $(x)=\frac{1}{3} x^{3}-12 x^{2}+7 x+5$
B) $f(x)=\frac{1}{3} x^{3}-\frac{11}{2} x^{2}+7 x+5$
C) $f(x)=\frac{1}{3} x^{3}-\frac{11}{2} x^{2}+7 x+1$
D) $f(x)=\frac{1}{3} x^{3}-12 x^{2}+7 x+1$

Question

Quizplus · Accepted Answer

The Answer of Solve the problem.
-The slope to the tangent line of a curve is given by $f^{\prime}(x)=x^{2}-11 x+7$. If the point $(0,5)$ is on the curve, find an equation of the curve.
A)f $(x)=\frac{1}{3} x^{3}-12 x^{2}+7 x+5$
B) $f(x)=\frac{1}{3} x^{3}-\frac{11}{2} x^{2}+7 x+5$
C) $f(x)=\frac{1}{3} x^{3}-\frac{11}{2} x^{2}+7 x+1$
D) $f(x)=\frac{1}{3} x^{3}-12 x^{2}+7 x+1$

Solve the Problem f′(x)=x2−11x+7f^{\prime}(x)=x^{2}-11 x+7f′(x)=x2−11x+7 If the Point (0,5)(0,5)(0,5) Is on the Curve, Find an Equation of the Curve

Solve the Problem $f^{\prime}(x)=x^{2}-11 x+7$ If the Point $(0,5)$ Is on the Curve, Find an Equation of the Curve