Evaluate.
-$\int 12 e^{-0.2 x} d x$
A) $\frac{12 e^{-0.2 x+1}}{-0.2 x+1}+C$
B) $-2.4 e^{-0.2 x}+C$
C) $12 e^{-0.2 x}+C$
D) $-60 e^{-0.2 x}+C$

Name: Evaluate. -$\int 12 e^{-0.2 x} d x$ A) $\frac{12 e^{-0.2 x+1}}{-0.2 x+1}+C$ B) $-2.4 e^{-0.2 x}+C$ C) $12 e^{-0.2 x}+C$ D) $-60 e^{-0.2 x}+C$
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The Answer of Evaluate.
-$\int 12 e^{-0.2 x} d x$
A) $\frac{12 e^{-0.2 x+1}}{-0.2 x+1}+C$
B) $-2.4 e^{-0.2 x}+C$
C) $12 e^{-0.2 x}+C$
D) $-60 e^{-0.2 x}+C$

Evaluate - ∫12e−0.2xdx\int 12 e^{-0.2 x} d x∫12e−0.2xdx A) 12e−0.2x+1−0.2x+1+C\frac{12 e^{-0.2 x+1}}{-0.2 x+1}+C−0.2x+112e−0.2x+1​+C

Evaluate
- $\int 12 e^{-0.2 x} d x$ A) $\frac{12 e^{-0.2 x+1}}{-0.2 x+1}+C$