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Solve the Problem v=46,300+100t2v=46,300+100 t^{2} , Where tt Is the Number of Years from Now

Question 210

Multiple Choice

Solve the problem.
-It is estimated that the total value of a stamp collection is given by the formula v=46,300+100t2v=46,300+100 t^{2} , where tt is the number of years from now. If the inflation rate is running continuously at 4%4 \% per year so that the (discounted) present value of an item that will be worth $v\$ v in tt years' time is given by p=ve.04t\mathrm{p}=\mathrm{ve}^{-.04 \mathrm{t}} . Sketch the graph of the discounted value as a function of time at which the stamp collection is sold. The graph has an absolute maximum at (0,46,300) (0,46,300) , and a local maximum at one other point. What is the value of tt at the local maximum? What is the discounted value of the collection at that time?
 Solve the problem. -It is estimated that the total value of a stamp collection is given by the formula  v=46,300+100 t^{2} , where  t  is the number of years from now. If the inflation rate is running continuously at  4 \%  per year so that the (discounted)  present value of an item that will be worth  \$ v  in  t  years' time is given by  \mathrm{p}=\mathrm{ve}^{-.04 \mathrm{t}} . Sketch the graph of the discounted value as a function of time at which the stamp collection is sold. The graph has an absolute maximum at  (0,46,300)  , and a local maximum at one other point. What is the value of  t  at the local maximum? What is the discounted value of the collection at that time?    A)   t=38 ; at which time the discounted value is  \$ 41,555.26 . B)   t=38.34 ; at which time the discounted value is  \$ 41,359.76 . C)   \mathrm{t}=37.73 ; at which time the discounted value is  \$ 41,709.19 . D)   t=39.59 ; at which time the discounted value is  \$ 40,623.55 .


A) t=38t=38 ; at which time the discounted value is $41,555.26\$ 41,555.26 .
B) t=38.34t=38.34 ; at which time the discounted value is $41,359.76\$ 41,359.76 .
C) t=37.73\mathrm{t}=37.73 ; at which time the discounted value is $41,709.19\$ 41,709.19 .
D) t=39.59t=39.59 ; at which time the discounted value is $40,623.55\$ 40,623.55 .

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