Solve the Problem $v$ Given By $v=1428 p(1 / 2)$ , Where $p$

Solve the problem.
-Water is discharged from a pipeline at a velocity $v$ given by $v=1428 p(1 / 2)$ , where $p$ is the pressure (in $\mathrm{psi}$ ) . If the water pressure is changing at a rate of $0.401 \mathrm{psi} / \mathrm{second}$ , find the acceleration $(\mathrm{dv} / \mathrm{dt})$ of the water when $\mathrm{p}=49 \mathrm{psi}$ .

A) $2004.2 \mathrm{ft} / \mathrm{s}^{2}$
B) $102 \mathrm{ft} / \mathrm{s}^{2}$
C) $49.98 \mathrm{ft} / \mathrm{s}^{2}$
D) $40.9 \mathrm{ft} / \mathrm{s}^{2}$