Solve the Problem $p=250-\frac{q}{4}$ , Where $p$ Is the Price (In Dollars) and Q Is the Quantity

Solve the problem.
-The demand for tickets at a concert hall can be approximated by $p=250-\frac{q}{4}$ , where $p$ is the price (in dollars) and q is the quantity demanded. Use implicit differentiation to find and interpret $\frac{\mathrm{dq}}{\mathrm{dp}}$ when $\mathrm{q}=600$ .

A) $\frac{\mathrm{dq}}{\mathrm{dp}}=-\frac{1}{4}$ means that if the price is increased by $\$ 1$ , the quantity demanded decreases by approximately $\frac{1}{4}$ tickets.
B) $\frac{\mathrm{dq}}{\mathrm{dp}}=-4$ means that if the price is decreased by $\$ 4$ , the quantity demanded increases by 1 ticket.
C) $\frac{\mathrm{dq}}{\mathrm{dp}}=-\frac{1}{4}$ means that if the price is decreased by $\$ 0.25$ , the quantity demanded increases by 1 ticket.
D) $\frac{\mathrm{dq}}{\mathrm{dp}}=-4$ means that if the price is increased by $\$ 1$ , the quantity demanded decreases by approximately 4 tickets.