Solve the problem.
-Suppose that the population of a certain type of insect in a region near the equator is given by $P(t)=13 \ln (t+12)$, where $t$ represents the time in days. Find the rate of change of the population when $\mathrm{t}=4$.
A) 3.3 insects/day
B) 1.1 insects/day
C) 0.8 insects/day
D) 1.7 insects/day

Question

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Suppose that the population of a certain type of insect in a region near the equator is given by $P(t)=13 \ln (t+12)$, where $t$ represents the time in days. Find the rate of change of the population when $\mathrm{t}=4$.
A) 3.3 insects/day
B) 1.1 insects/day
C) 0.8 insects/day
D) 1.7 insects/day

Solve the Problem P(t)=13ln⁡(t+12)P(t)=13 \ln (t+12)P(t)=13ln(t+12) , Where ttt Represents the Time in Days

Solve the Problem $P(t)=13 \ln (t+12)$ , Where $t$ Represents the Time in Days