Solve the problem.
-A ball is thrown vertically upward from the ground at a velocity of 118 feet per second. Its distance from the ground after $t$ seconds is given by $s(t)=-16 t^{2}+118 t$. How fast is the ball moving 7 seconds after being thrown?
A) $6 \mathrm{ft}$ per sec
B) $-106 \mathrm{ft}$ per sec
C) $42 \mathrm{ft}$ per sec
D) $-127 \mathrm{ft}$ per sec

Question

Quizplus · Accepted Answer

The velocity of the ball is the derivative of the distance function: $v(t) = s'(t) = -32t + 118$. At $t = 7$ seconds, $v(7) = -32(7) + 118 = -106$ ft/sec.

Solve the Problem ttt Seconds Is Given By s(t)=−16t2+118ts(t)=-16 t^{2}+118 ts(t)=−16t2+118t How Fast Is the Ball Moving 7 Seconds After

Solve the Problem $t$ Seconds Is Given By $s(t)=-16 t^{2}+118 t$ How Fast Is the Ball Moving 7 Seconds After