Find the derivative.
-$y=\frac{x^{2}+8 x+3}{\sqrt{x}}$
A) $y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}$
B) $y^{\prime}=\frac{2 x+8}{x}$
C) $y^{\prime}=\frac{3 x^{2}+8 x-3}{x}$
D) $y^{\prime}=\frac{3 x^{2}+8 x-3}{2 x^{3 / 2}}$

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The Answer of Find the derivative.
-$y=\frac{x^{2}+8 x+3}{\sqrt{x}}$
A) $y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}$
B) $y^{\prime}=\frac{2 x+8}{x}$
C) $y^{\prime}=\frac{3 x^{2}+8 x-3}{x}$
D) $y^{\prime}=\frac{3 x^{2}+8 x-3}{2 x^{3 / 2}}$

Find the Derivative y=x2+8x+3xy=\frac{x^{2}+8 x+3}{\sqrt{x}}y=x​x2+8x+3​ A) y′=2x+82x3/2y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}y′=2x3/22x+8​ B) y′=2x+8xy^{\prime}=\frac{2 x+8}{x}y′=x2x+8​

Find the Derivative $y=\frac{x^{2}+8 x+3}{\sqrt{x}}$ A) $y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}$ B) $y^{\prime}=\frac{2 x+8}{x}$