Find the average rate of change for the function over the given interval.
-$y=x^{3}+x^{2}-8 x-7$ between $x=0$ and $x=2$
A) -2
B) $\frac{1}{2}$
C) -28
D) $-\frac{1}{6}$

Question

Quizplus · Accepted Answer

The average rate of change is the slope of the secant line between the two points. The slope of the secant line is:$$m=\frac{f(2)-f(0)}{2-0}=\frac{(2^3+2^2-8\cdot2-7)-(0^3+0^2-8\cdot0-7)}{2-0}=\frac{-14}{2}=-7$$Therefore, the average rate of change is -7.

Find the Average Rate of Change for the Function Over y=x3+x2−8x−7y=x^{3}+x^{2}-8 x-7y=x3+x2−8x−7

Find the Average Rate of Change for the Function Over $y=x^{3}+x^{2}-8 x-7$