Find the standard deviation for the given data.
-Christine is currently taking college astronomy. The instructor often gives quizzes. On the past seven quizzes, Christine got the following scores:
$\begin{array}{lllllll}54 & 1933.0 & 24 & 15 & 50 & 78\end{array}$
Round results to one decimal place.
A) 22.7
B) $13,751.0$
C) $10,647.0$
D) 33.0

Question

Quizplus · Accepted Answer

The standard deviation is a measure of how spread out the data is. The larger the standard deviation, the more spread out the data is. In this case, the data is very spread out, with a standard deviation of 22.7.

Find the Standard Deviation for the Given Data 541933.024155078\begin{array}{lllllll}54 & 1933.0 & 24 & 15 & 50 & 78\end{array}54​1933.0​24​15​50​78​

Find the Standard Deviation for the Given Data $\begin{array}{lllllll}54 & 1933.0 & 24 & 15 & 50 & 78\end{array}$