Solve the problem.
-There are 10 members on a board of directors. If they must elect a chairperson, a secretary, and a treasurer, how many different slates of candidates are possible?
A) 1000
B) 720
C) 120
D) $3,628,800$

Question

Quizplus · Accepted Answer

The number of ways to elect a chairperson, a secretary, and a treasurer from 10 members is a permutation problem. The formula for permutations is $ nPr = \frac{n!}{(n-r)!} $. Here, $ n = 10 $ and $ r = 3 $. So, $ 10P3 = \frac{10!}{(10-3)!} = \frac{10 \times 9 \times 8}{1} = 720 $.

Solve the Problem 3,628,8003,628,8003,628,800

Solve the Problem $3,628,800$