Solve the problem.
-A manufacturer makes three different drinks. Drink 1 contains $20 \%$ juice and $80 \%$ carbonated water. Drink 2 contains $50 \%$ juice and 50\% carbonated water. Drink 3 contains $80 \%$ juice and $20 \%$ carbonated water. The manufacturer currently has available 60 liters of juice and 180 liters of carbonated water. Drink 1 sells for $\$ 1$ per liter, Drink 2 sells for $\$ 2$ per liter, and Drink 3 sells for $\$ 3.80$ per liter. How many liters of each drink should the manufacturer make to maximize revenues?
A) 220.0 liters of Drink 1, 0 liters of Drink 2, 20.0 liters of Drink 3
B) 190.0 liters of Drink 1, 60 liters of Drink 2, 30.0 liters of Drink 3
C) 200.0 liters of Drink 1, 40 liters of Drink 2, 40.0 liters of Drink 3
D) 122.0 liters of Drink 1, 20 liters of Drink 2, 10.0 liters of Drink 3

Question

Quizplus · Accepted Answer

The correct answer is A because it maximizes the revenue by producing the most profitable drink, Drink 1, and using all of the available juice and carbonated water.

Solve the Problem 20%20 \%20% Juice And 80%80 \%80% Carbonated Water 50%50 \%50%

Solve the Problem $20 \%$ Juice And $80 \%$ Carbonated Water $50 \%$