Determine the vertex of the parabola.
-$f(x)=x^{2}-10 x+29$
A) $(4,5)$
B) $(5,0)$
C) $(5,4)$
D) $(0,4)$

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $f(x) = ax^2 + bx + c$ is given by $(h, k)$, where $h = -\frac{b}{2a}$. For $f(x) = x^2 - 10x + 29$, $a = 1$ and $b = -10$, so $h = -\frac{-10}{2 \times 1} = 5$. Substitute $x = 5$ into the function to find $k$: $f(5) = 5^2 - 10 \times 5 + 29 = 25 - 50 + 29 = 4$. Thus, the vertex is $(5, 4)$.

Determine the Vertex of the Parabola f(x)=x2−10x+29f(x)=x^{2}-10 x+29f(x)=x2−10x+29 A) (4,5)(4,5)(4,5) B) (5,0)(5,0)(5,0) C) (5,4)(5,4)(5,4)

Determine the Vertex of the Parabola $f(x)=x^{2}-10 x+29$ A) $(4,5)$ B) $(5,0)$ C) $(5,4)$