Solve the problem.
-A rectangular garden has dimensions of 21 feet by 14 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 344 square feet?
A) $6 \mathrm{ft}$
B) $5 \mathrm{ft}$
C) $6.5 \mathrm{ft}$
D) $4 \mathrm{ft}$

Question

Quizplus · Accepted Answer

The area of the garden is $21 \times 14 = 294$ square feet. The total area with the path is $294 + 344 = 638$ square feet. Let $x$ be the width of the path. The dimensions of the garden with the path are $(21 + 2x)$ by $(14 + 2x)$. The equation is $(21 + 2x)(14 + 2x) = 638$. Solving for $x$, we find $x = 4$ feet.

Solve the Problem 6ft6 \mathrm{ft}6ft B) 5ft5 \mathrm{ft}5ft C) 6.5ft6.5 \mathrm{ft}6.5ft D) 4ft4 \mathrm{ft}4ft

Solve the Problem $6 \mathrm{ft}$ B) $5 \mathrm{ft}$ C) $6.5 \mathrm{ft}$ D) $4 \mathrm{ft}$