Use factoring to solve the equation.
-$\mathrm{r}^{2}+4 \mathrm{r}+4=14$
A) $-2+\sqrt{14},-2-\sqrt{14}$
B) $\sqrt{14}, \sqrt{14}$
C) $2+\sqrt{14}, 2-\sqrt{14}$
D) 12

Question

Quizplus · Accepted Answer

First, subtract 14 from both sides to get $r^2 + 4r - 10 = 0$. Then, use the quadratic formula $r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 1$, $b = 4$, and $c = -10$. This gives $r = \frac{-4 \pm \sqrt{16 + 40}}{2}$, which simplifies to $r = -2 \pm \sqrt{14}$.

Use Factoring to Solve the Equation r2+4r+4=14\mathrm{r}^{2}+4 \mathrm{r}+4=14r2+4r+4=14 A) −2+14,−2−14-2+\sqrt{14},-2-\sqrt{14}−2+14​,−2−14​ B) 14,14\sqrt{14}, \sqrt{14}14​,14​

Use Factoring to Solve the Equation $\mathrm{r}^{2}+4 \mathrm{r}+4=14$ A) $-2+\sqrt{14},-2-\sqrt{14}$ B) $\sqrt{14}, \sqrt{14}$