Verify that the first four terms of the Fourier series for the sawtooth function below are:
$f(t)=\frac{1}{2}-\frac{1}{\pi}\left[\sin 2 \pi t+\frac{1}{2} \sin 4 \pi t+\frac{1}{3} \sin 6 \pi t\right]$

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The Answer of Verify that the first four terms of the Fourier series for the sawtooth function below are:
$f(t)=\frac{1}{2}-\frac{1}{\pi}\left[\sin 2 \pi t+\frac{1}{2} \sin 4 \pi t+\frac{1}{3} \sin 6 \pi t\right]$

Verify That the First Four Terms of the Fourier Series f(t)=12−1π[sin⁡2πt+12sin⁡4πt+13sin⁡6πt]f(t)=\frac{1}{2}-\frac{1}{\pi}\left[\sin 2 \pi t+\frac{1}{2} \sin 4 \pi t+\frac{1}{3} \sin 6 \pi t\right]f(t)=21​−π1​[sin2πt+21​sin4πt+31​sin6πt]

Verify That the First Four Terms of the Fourier Series $f(t)=\frac{1}{2}-\frac{1}{\pi}\left[\sin 2 \pi t+\frac{1}{2} \sin 4 \pi t+\frac{1}{3} \sin 6 \pi t\right]$