Find the instantaneous velocity and acceleration at the given time for the straight-line motion described by the equation: $s=(t+2)^{4}-\frac{1}{(t+2)^{2}}$ at $1.000 \mathrm{~s}$, where $s$ is in centimetres.

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The Answer of Find the instantaneous velocity and acceleration at the given time for the straight-line motion described by the equation: $s=(t+2)^{4}-\frac{1}{(t+2)^{2}}$ at $1.000 \mathrm{~s}$, where $s$ is in centimetres.

Find the Instantaneous Velocity and Acceleration at the Given Time s=(t+2)4−1(t+2)2s=(t+2)^{4}-\frac{1}{(t+2)^{2}}s=(t+2)4−(t+2)21​

Find the Instantaneous Velocity and Acceleration at the Given Time $s=(t+2)^{4}-\frac{1}{(t+2)^{2}}$