Kirchhoff's rules were applied to a three-loop network. Solve for currents $l_{1}, l_{2}$, and $l_{3}$ in this resulting system of equations:
$76.0 I_{1}-25.0 I_{2}-50.0 I_{3}=10.0$
$-25.0 l_{1}+56.0 I_{2}-1.00 I_{3}=0.00$
$-50.0 l_{1}-1.0 I_{2}+106 l_{3}=0.00$

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The Answer of Kirchhoff's rules were applied to a three-loop network. Solve for currents $l_{1}, l_{2}$, and $l_{3}$ in this resulting system of equations:
$76.0 I_{1}-25.0 I_{2}-50.0 I_{3}=10.0$
$-25.0 l_{1}+56.0 I_{2}-1.00 I_{3}=0.00$
$-50.0 l_{1}-1.0 I_{2}+106 l_{3}=0.00$

Kirchhoff's Rules Were Applied to a Three-Loop Network l1,l2l_{1}, l_{2}l1​,l2​ , And

Kirchhoff's Rules Were Applied to a Three-Loop Network $l_{1}, l_{2}$ , And