A box weighing 615 pounds is held in place on an inclined plane that has an angle of 14°. What force is required to hold it in place? Round to the nearest pound.
A) 149 pounds
B) 609 pounds
C) 597 pounds
D) no solution

Question

Quizplus · Accepted Answer

The force required to hold the box in place on an inclined plane can be calculated using the formula $F = mg\sin(\theta)$, where $F$ is the force, $m$ is the mass of the object, $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$), and $\theta$ is the angle of the incline. However, since the weight is given in pounds, a direct approach using the weight and the sine of the angle can be applied, bypassing the need to convert weight to mass and use $g$. The force required is thus $615 \times \sin(14^\circ)$. Calculating this gives a value close to 149 pounds, rounding to the nearest pound.

A Box Weighing 615 Pounds Is Held in Place on an Inclined