Find the second derivative of $y=y^{2}-3 x^{4}+4$.
A) $y^{\prime \prime}=\frac{72 x^{2} y-36 x^{2}-288 x^{6}}{(1-2 y)^{3}}$
B) $y^{\prime \prime}=\frac{\left(72 x^{2} y-36 x^{2}\right)(1-2 y)-288 x^{6}}{(1-2 y)^{2}}$
C) $y^{\prime \prime}=\frac{(1-2 y)\left(36 x^{2} y-18 x^{2}\right)}{(1-2 y)^{3}}$
D) $y^{\prime \prime}=\frac{\left(72 x^{2} y-36 x^{2}\right)(1-2 y)-288 x^{6}}{(1-2 y)^{3}}$

Question

Quizplus · Accepted Answer

The second derivative is found by differentiating the first derivative, considering the implicit differentiation of $y$ with respect to $x$.

Find the Second Derivative Of y=y2−3x4+4y=y^{2}-3 x^{4}+4y=y2−3x4+4 A) y′′=72x2y−36x2−288x6(1−2y)3y^{\prime \prime}=\frac{72 x^{2} y-36 x^{2}-288 x^{6}}{(1-2 y)^{3}}y′′=(1−2y)372x2y−36x2−288x6​

Find the Second Derivative Of $y=y^{2}-3 x^{4}+4$
A) $y^{\prime \prime}=\frac{72 x^{2} y-36 x^{2}-288 x^{6}}{(1-2 y)^{3}}$