Find the equation of the circle with radius 4 and center (-2, -6) in standard form. A) (x - 2)² + (y - 6)² = 16 B) (x + 2)² + (y + 6)² = 4 C) (x + 2)² + (y + 6)² = 16 D) (x - 2)² + (y - 6)² = 4

Question

Quizplus · Accepted Answer

The standard form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. For a center at $(-2, -6)$ and radius $4$, the equation is $(x + 2)^2 + (y + 6)^2 = 16$.

Find the Equation of the Circle with Radius 4 and Center