Suppose m and n are positive integers such that log m $\approx$ 143.33 and log n $\approx$ 217.34. How many digits does mn have?
A) 361
B) 31,151
C) 360
D) Cannot be determined

Question

Quizplus · Accepted Answer

The number of digits of a number x is given by the formula floor(log10(x)) + 1. Since log(mn) = log(m) + log(n), we have log(mn) ≈ 143.33 + 217.34 = 360.67. Therefore, the number of digits in mn is floor(360.67) + 1 = 361.

Suppose M and N Are Positive Integers Such That Log ≈\approx≈

Suppose M and N Are Positive Integers Such That Log $\approx$