Use the remainder theorem to find $\mathbf{P}(\mathbf{k})$.
-$k=2 ; P(x)=3 x^{5}+5 x^{3}+3 x^{2}-2$
A) 146
B) 147
C) -122
D) -126

Question

Quizplus · Accepted Answer

The remainder theorem states that the remainder of the division of a polynomial $P(x)$ by $x - k$ is $P(k)$. Substituting $k = 2$ into $P(x) = 3x^5 + 5x^3 + 3x^2 - 2$, we get $P(2) = 3(2)^5 + 5(2)^3 + 3(2)^2 - 2 = 3(32) + 5(8) + 3(4) - 2 = 96 + 40 + 12 - 2 = 146$.

Use the Remainder Theorem to Find P(k)\mathbf{P}(\mathbf{k})P(k) - k=2;P(x)=3x5+5x3+3x2−2k=2 ; P(x)=3 x^{5}+5 x^{3}+3 x^{2}-2k=2;P(x)=3x5+5x3+3x2−2

Use the Remainder Theorem to Find $\mathbf{P}(\mathbf{k})$
- $k=2 ; P(x)=3 x^{5}+5 x^{3}+3 x^{2}-2$