Find a general term for the geometric sequence.
-$32,-16, \ldots$
A) $a_{n}=32\left(\frac{1}{2}\right)^{n-1}$

B) $a_{n}=32\left(-\frac{1}{2}\right)^{n-1}$

C) $a_{n}=32\left(-\frac{1}{3}\right)^{n-1}$

D) $a_{n}=32(-2)^{n-1}$

Question

Find a general term for the geometric sequence.
-$32,-16, \ldots$
A) $a_{n}=32\left(\frac{1}{2}\right)^{n-1}$

B) $a_{n}=32\left(-\frac{1}{2}\right)^{n-1}$

C) $a_{n}=32\left(-\frac{1}{3}\right)^{n-1}$

D) $a_{n}=32(-2)^{n-1}$

Quizplus · Accepted Answer

The sequence starts at 32 and each term is multiplied by $-\frac{1}{2}$ to get the next term (e.g., $32 \times -\frac{1}{2} = -16$), which matches the formula in choice B: $a_{n}=32\left(-\frac{1}{2}\right)^{n-1}$.

Find a General Term for the Geometric Sequence 32,−16,…32,-16, \ldots32,−16,… A) an=32(12)n−1a_{n}=32\left(\frac{1}{2}\right)^{n-1}an​=32(21​)n−1

Find a General Term for the Geometric Sequence $32,-16, \ldots$ A) $a_{n}=32\left(\frac{1}{2}\right)^{n-1}$