Evaluate the series
-$\sum_{i=1}^{4}\left(i^{2}-4 i-3\right)$
A) -22
B) -2
C) -18
D) 23

Question

Quizplus · Accepted Answer

The series can be evaluated by plugging in the values of $i$ from 1 to 4 into the given expression $i^2 - 4i - 3$ and summing them up. For $i = 1$, the expression is $1^2 - 4(1) - 3 = 1 - 4 - 3 = -6$. For $i = 2$, it is $2^2 - 4(2) - 3 = 4 - 8 - 3 = -7$. For $i = 3$, it is $3^2 - 4(3) - 3 = 9 - 12 - 3 = -6$. For $i = 4$, it is $4^2 - 4(4) - 3 = 16 - 16 - 3 = -3$. Summing these values gives $-6 - 7 - 6 - 3 = -22$.

Evaluate the Series - ∑i=14(i2−4i−3)\sum_{i=1}^{4}\left(i^{2}-4 i-3\right)∑i=14​(i2−4i−3) A) -22 B) -2 C) -18 D) 23

Evaluate the Series
- $\sum_{i=1}^{4}\left(i^{2}-4 i-3\right)$ A) -22
B) -2
C) -18
D) 23